A uniform-width boardwalk is built around the inside edge of a rectangular parkland that is 30 m by 5 m. If the boardwalk takes up 20% of the lot, how wide is the boardwalk to the nearest centimetre?
I know that the total area= 150m^2
boardwalk area= 30m^2 and the parkway area is 120m^2.
I don't know what to do with these numbers.
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To find the width of the boardwalk, we can use the equation:
Boardwalk area = Total area × Percentage of the lot
Given that the boardwalk area is 30m^2 and the total area is 150m^2 (30m × 5m), and the boardwalk takes up 20% of the lot, we can set up the equation as follows:
30m^2 = 150m^2 × 0.20
Simplifying the equation:
30m^2 = 30m^2
This equation is already balanced, so it tells us that our calculations are correct and there are no mathematical errors.
From this equation, we can conclude that the width of the boardwalk is the same as the length of the parkland, which is 5 meters.
To find the width of the boardwalk, we can start by calculating the area of the boardwalk. Given that the boardwalk takes up 20% of the total area, we can find its area by multiplying the total area by 0.20:
Area of boardwalk = 150 m^2 * 0.20 = 30 m^2
Now that we know the area of the boardwalk is 30 m^2, we can find its width by dividing the area by the length of the parkland (30 m):
Width of the boardwalk = 30 m^2 / 5 m = 6 m
However, since we need the width in centimeters, let's convert the width from meters to centimeters. Since there are 100 centimeters in a meter, we can multiply the width by 100:
Width of the boardwalk = 6 m * 100 cm/m = 600 cm
Therefore, the width of the boardwalk is 600 centimeters (to the nearest centimeter).