A fair coin is tossed two times in succession. The set of equally likely outcomes is {HH, HT, TH, TT}. Find the probability of getting exactly one head.

The probability of getting one head

To find the probability of getting exactly one head when tossing a fair coin two times, we can count the number of outcomes that satisfy this condition and divide it by the total number of possible outcomes.

Let's list the outcomes that have exactly one head: {HT, TH}. So, there are two outcomes that satisfy the condition.

The total number of possible outcomes is four, as mentioned in the question.

Therefore, the probability of getting exactly one head is 2/4, or simplified: 1/2.

To find the probability of getting exactly one head when tossing a fair coin two times, we need to determine how many outcomes have exactly one head and calculate the ratio of those outcomes to the total number of equally likely outcomes.

In this case, the set of equally likely outcomes is {HH, HT, TH, TT}, with four possible outcomes.

Now, let's determine how many outcomes have exactly one head:
- HH: Two heads (does not meet the condition)
- HT: One head (meets the condition)
- TH: One head (meets the condition)
- TT: No heads (does not meet the condition)

Out of the four possible outcomes, two meet the condition of having exactly one head.

Therefore, the probability of getting exactly one head is 2/4, which simplifies to 1/2.

So, the probability of getting exactly one head when tossing a fair coin two times is 1/2.

1/2 or 50%