Determine the number of moles of sodium hydroxide produced when 2 moles of sodium and 3 moles of water react to form sodium hydroxide and hydrogen gas.
To determine the number of moles of sodium hydroxide produced, we need to use the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction is as follows:
2 Na + 2 H2O -> 2 NaOH + H2
From the balanced equation, we can see that 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen gas.
Since we are given that 2 moles of sodium and 3 moles of water are reacting, we need to determine the limiting reagent in order to find the number of moles of sodium hydroxide produced.
First, we need to calculate the moles of sodium and water available:
Moles of sodium = 2 moles
Moles of water = 3 moles
Next, we compare the moles of sodium with the moles of water to determine the limiting reagent. The limiting reagent is the reactant that is completely consumed and limits the amount of product that can be formed.
From the balanced equation, we know that 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide. Therefore, the mole ratio of sodium to water is 2:2, or 1:1.
Since we have more moles of water (3 moles) than sodium (2 moles), water is in excess, and sodium is the limiting reagent.
Now, we can determine the number of moles of sodium hydroxide produced using the mole ratio from the balanced equation.
From the balanced equation, we know that 2 moles of sodium hydroxide are produced for every 2 moles of sodium reacted.
Since we have 2 moles of sodium, we can calculate the moles of sodium hydroxide produced as:
2 moles of sodium x (2 moles of sodium hydroxide / 2 moles of sodium) = 2 moles of sodium hydroxide
Therefore, when 2 moles of sodium and 3 moles of water react to form sodium hydroxide and hydrogen gas, the number of moles of sodium hydroxide produced is 2 moles.
To determine the number of moles of sodium hydroxide produced in the reaction, we first need to write a balanced chemical equation for the reaction.
The given reaction is:
2 Na + 3 H2O → 2 NaOH + H2
From the balanced chemical equation, we can see that 2 moles of sodium (Na) react with 3 moles of water (H2O) to produce 2 moles of sodium hydroxide (NaOH).
Therefore, the number of moles of sodium hydroxide produced is also 2 moles.
In summary:
Number of moles of sodium hydroxide produced = 2 moles
2Na + 2H2O = 2NaOH + H2
now just multiply everything by 3/2