a body is projected horizontally with a velocity of 20m/s from height of a tower 160m above the ground calculate the time of flight distance from the foot of the tower to where the object land

how long does it take to fall 160m? The horizontal speed does not affect that.

4.9t^2 = 160

Now, the horizontal speed does not change, so the body travels

20t meters

H:160m

t:T. ay:9.8
Uy : 0
H: uy*t+1/2ay*t*t
160=0*T+1/2 * 9.8*TT
160=1/2*9.8*TT
160*2/9.8=TT
√160/√4.9=T
4√10/7=T

To calculate the time of flight and the distance from the foot of the tower where the object lands, we can use the equations of motion.

1. First, let's determine the time of flight:
Since the body is projected horizontally, its initial vertical velocity is 0 m/s. The acceleration due to gravity, g, is approximately 9.8 m/s².

Using the formula for vertical displacement: d = (v0 * t) + (0.5 * g * t²),
where d = vertical displacement, v0 = initial vertical velocity, g = acceleration due to gravity, and t = time.

We know that the vertical displacement, d, is equal to the initial height of the tower, which is 160 m.
Therefore, we can rewrite the equation as: 160 = 0 + (0.5 * 9.8 * t²).

Simplifying the equation, we have: 160 = 4.9 * t².

Dividing both sides by 4.9, we get: t² = 32.65.

Taking the square root of both sides, we find: t ≈ 5.71 seconds (rounded to two decimal places).

So, the time of flight is approximately 5.71 seconds.

2. Next, let's calculate the distance from the foot of the tower where the object lands:
Since the body is projected horizontally, the horizontal velocity remains constant throughout the motion. Therefore, the horizontal distance traveled can be calculated using the formula: distance = horizontal velocity * time.

In this case, the horizontal velocity is 20 m/s (given).
Using the calculated time of flight of 5.71 seconds, we can plug in these values into the formula: distance = 20 * 5.71.

Calculating this, we find: distance ≈ 114.2 meters (rounded to one decimal place).

So, the distance from the foot of the tower where the object lands is approximately 114.2 meters.

what if i said it is u=20 h=160

20/10=2m/s 160/10=16
t=8m/s
1.time of flight =8m/s 16/2=8m/s
2.distance=20*10=200/10=2
distance
=2*10/10=2mls
H=8m/s
V=2m/s

thats how i got my answer collect me if am worng