suppose that sample of beef broth initially contains 16 bacterial cells. after 4.0 h, there are 1.6 x 106 bacterial cells in the sample. calculate the growth rate of the bacterial population for the given time interval. (record your answer in scientific notation: x x 10n )

Question

suppose that sample of beef broth initially contains 16 bacterial cells. after 4.0 h, there are 1.6 x 106 bacterial cells in the sample. calculate the growth rate of the bacterial population for the given time interval. (record your answer in scientific notation: x x 10n )

Answer 1

PR= V(present)- V(past) divided by V(past)x100

PR= (1.6x106)- 16
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16
PR= 153.6
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16
PR= 9.5 x 100

Answer 2

Well, well, well, it seems we have a beefy question here! Let's crunch those numbers, shall we?

We start with 16 bacterial cells and end up with 1.6 x 10^6 cells after 4.0 hours. To get the growth rate, we need to calculate the increase in the number of cells per unit time.

The increase in cell count is 1.6 x 10^6 - 16 = 1.6 x 10^6. It's like a bacterial flash mob in that beef broth!

Now, we divide the increase in cell count by the duration or time interval, which is 4.0 hours: (1.6 x 10^6) / (4.0) = 4.0 x 10^5.

So, the growth rate of the bacterial population for the given time interval is 4.0 x 10^5 cells per hour. Quite exponential, wouldn't you say?

Answer 3

To calculate the growth rate of the bacterial population, we can use the formula:

Growth Rate = (Final Population - Initial Population) / (Initial Population * Time)

Given:
Initial Population (N0) = 16 bacterial cells
Final Population (Nt) = 1.6 x 10^6 bacterial cells
Time (t) = 4.0 hours

Substituting these values into the formula, we get:

Growth Rate = (1.6 x 10^6 - 16) / (16 * 4.0)

Growth Rate = (1.6 x 10^6 - 16) / 64

Growth Rate = (1.599984 x 10^6) / 64

Growth Rate ≈ 2.49 x 10^4

Therefore, the growth rate of the bacterial population for the given time interval is approximately 2.49 x 10^4.

Answer 4

To calculate the growth rate of the bacterial population, we can use the formula:

Growth Rate = (Final Number of Cells - Initial Number of Cells) / (Initial Number of Cells * Time)

Let's apply this formula to the given data:

Initial Number of Cells (N₀) = 16
Final Number of Cells (Nₜ) = 1.6 x 10^6
Time (t) = 4.0 hours

Substituting these values into the formula, we get:

Growth Rate = (1.6 x 10^6 - 16) / (16 * 4.0)

Simplifying this expression:

Growth Rate = (1.6 x 10^6 - 16) / 64

Now calculating:

Growth Rate ≈ 2.5 x 10^4

Therefore, the growth rate of the bacterial population for the given time interval is approximately 2.5 x 10^4.