A towns' population, P(x), is given by the function P(x) =2700x + 21000 where x represents the years since 2003.

The population will reach 83,400 in ______

The population in 2010 will be ______

2700x+21000 = 83400

just solve for x

2010 is 7 years after 2003, so just plug in x=7 for P(x)

thanks!!

To find the year when the population reaches 83,400, we need to set P(x) equal to 83,400 and solve for x.

The given function is P(x) = 2700x + 21000.

So, we substitute 83,400 for P(x):

83,400 = 2700x + 21000

To solve for x, we need to isolate it on one side of the equation:

83,400 - 21,000 = 2700x

62,400 = 2700x

Now, divide both sides of the equation by 2700:

62,400 / 2700 = x

x ≈ 23.11

Therefore, the population will reach 83,400 in approximately 23.11 years after 2003. To determine the year, we need to add x to 2003:

2003 + 23.11 ≈ 2026.11

So, the population will reach 83,400 in the year 2026.

To find the population in 2010, we need to substitute x = 2010 - 2003 = 7 into the given function:

P(7) = 2700(7) + 21,000

P(7) = 18,900 + 21,000

P(7) = 39,900

Therefore, the population in 2010 will be 39,900.