a box contains red markers ,blue markers amd green markers . there are more blue makers than red .the probability of randomly selecting a blue marker from the box is 1/5 . that is a possible probability that a randomly selected marker from he box is red?

A box contains 2 blue markers, 5 green markers and 3 yellow markers. What is the probability of drawing a blue marker, replacing it, then drawing a yellow marker?

Write as a fraction in simplest form

To determine the possible probability of randomly selecting a red marker from the box, we need to gather all the information provided.

Firstly, we know that the box contains red markers, blue markers, and green markers.

Secondly, we are informed that there are more blue markers than red markers.

Lastly, we are given the probability of randomly selecting a blue marker, which is 1/5.

Based on this information, we can calculate the probability of selecting a red marker by using the concept of complement.

The complement of an event is the probability of that event not occurring. In this case, the complement event is selecting a blue marker.

To find the probability of selecting a red marker, we can take the complement of selecting a blue marker, which is 1 - 1/5 = 4/5.

Therefore, the possible probability of randomly selecting a red marker from the box is 4/5.

Well, if blue probility is .2, then red has to be less, so if pr<.2, that is a valid probility for red.

Jordan 12