segment jk has coordinates j(3 -6) and k(-3 2) when segment jk is dilated with a scale factor -4, what are the coordinates of J' and K'?
J'(7,-2) and K'(1,6)
J'(-12,24) and K'(12,-8) <--? or D
J'(-1,-10) and K'(12,-8)
J'(-3/4,3/2) and K'(3/4,-1/2)
well you multiply by -4, so B looks good.
To dilate a line segment, you need to multiply the coordinates of each point by the scale factor.
In this case, the scale factor is -4. To find the coordinates of J' and K', we need to multiply the x and y coordinates of J and K by -4.
For J' (x-coordinate):
x' = x * scale factor
= 3 * -4
= -12
For J' (y-coordinate):
y' = y * scale factor
= -6 * -4
= 24
So, the coordinates of J' are (-12, 24).
For K' (x-coordinate):
x' = x * scale factor
= -3 * -4
= 12
For K' (y-coordinate):
y' = y * scale factor
= 2 * -4
= -8
So, the coordinates of K' are (12, -8).
Therefore, the correct answer is J'(-12,24) and K'(12,-8).