what is the Mr of CO2?
Use this to calculate the mass of co2 produced when 1kg of CaCO3 is heated....
(what are the answers?)
MT!!!
Mr????? Do you mean the molecular mass? I assume so. it is 44amu, or 44 grams/mole
CaCO3 >>>> CaO + CO2
moles CaCO3= 1000g/(100g/mol=10moles
so according to the balanced equation, you should get 10 moles CO2, or 440 grams.
TVM!!
To calculate the molar mass of CO2 (carbon dioxide), we need to consider the atomic masses of carbon (C) and oxygen (O). The atomic mass of carbon is approximately 12.01 grams per mole (g/mol), and the atomic mass of oxygen is approximately 16.00 g/mol.
So, the molecular mass of CO2 is calculated by adding the atomic masses of carbon and two oxygen atoms:
Molecular mass of CO2 = (atomic mass of C) + 2 x (atomic mass of O)
= 12.01 g/mol + 2 x 16.00 g/mol
= 44.01 g/mol
Therefore, the molar mass of CO2 is approximately 44.01 g/mol.
To calculate the mass of CO2 produced when 1 kg of CaCO3 (calcium carbonate) is heated, we need to first determine the percentage of CO2 in CaCO3. The molar mass of CaCO3 can be calculated by adding the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms:
Molar mass of CaCO3 = (atomic mass of Ca) + (atomic mass of C) + 3 x (atomic mass of O)
= atomic mass of Ca + 12.01 g/mol + 3 x 16.00 g/mol
Once you have the molar mass of CaCO3, you can convert 1 kg to grams (1 kg = 1000 grams) and use the molar mass to calculate the moles of CaCO3. Then, using the ratio of moles from the balanced equation for the decomposition of CaCO3, you can determine the moles of CO2 produced. Finally, use the molar mass of CO2 to calculate the mass of CO2 produced.
Without additional information like the balanced equation or the percentage of CO2 produced during the reaction, it is not possible to provide the exact answer.