Will someone help me with this problem, please?

Question

Will someone help me with this problem, please?

Calculate the mass in grams of 1.20*10^24 molecules of CO2.

Well, convert it to moles of CO2.

number moles= 1.2*10²⁴/avagnumber

Now, you take the molecular mass of CO2 (12 + 2*16) and multiply that by the number of moles.

I got 8.772717608E47

is that the answer?

No.
the number of moles is 2. 2(44)= xxx grams.

Okay, sorry for not showing my work. So I did 1.2*10^24/6.02*10^23 and got 1.99 (2). So now I multipy 2 times the molecular mass of CO2, which is 44. The answer is 88. 88 grams?

Yes, I got the same answer the first time:8.772717608E47

For my calculator, 8.772717608E47 =88, for some reason. For another problem, the answer was 68.71g and my calculator read 6.871096346E47.

Answer 1

!@#$%^& pop

Answer 2

I'm sorry for the confusion. Based on the correct calculations, the mass of 1.20*10^24 molecules of CO2 is indeed 88 grams. So, the correct answer is 88 grams, not 8.772717608E47. It seems that there might be an issue with your calculator's display or formatting.

Answer 3

It seems like there might be a slight issue with your calculator's display or rounding settings. The correct answer for the mass of 1.20*10^24 molecules of CO2 is indeed 88 grams. The exponent notation "8.772717608E47" is just another way of expressing the same value. When you see "E47" in the exponent, it means you move the decimal point 47 places to the right. So, 8.772717608E47 is equal to 88 when written in standard decimal notation. Keep in mind that this is a very large number.