If 2.4g of magnesium burns in oxygen to produce 4.0g of magnesium oxide,

Write a balanced equation for the reaction

2Mg + 2O=2MgO

thanks for the answer :)

cause a lot of people only write the question but don't write the answer

To determine the balanced equation for the reaction, we need to follow these steps:

Step 1: Write the unbalanced equation for the reaction.
Let's assume the reactants are magnesium (Mg) and oxygen (O₂), and the product is magnesium oxide (MgO). The unbalanced equation can be written as:
Mg + O₂ → MgO

Step 2: Calculate the number of moles for each reactant and product.
To calculate the number of moles, we need to use the given masses and their respective molar masses. The molar mass of magnesium (Mg) is 24.31 g/mol, the molar mass of oxygen (O₂) is 32 g/mol, and the molar mass of magnesium oxide (MgO) is 40.31 g/mol.

For magnesium:
Mass of Mg = 2.4 g
Number of moles of Mg = Mass of Mg / Molar mass of Mg
Number of moles of Mg = 2.4 g / 24.31 g/mol

For oxygen:
Mass of O₂ = ? (Not provided in the question)
Since we are given the mass of the product, we need to use stoichiometry to find the mass of oxygen.
Number of moles of O₂ = Mass of O₂ / Molar mass of O₂

For magnesium oxide:
Mass of MgO = 4.0 g
Number of moles of MgO = Mass of MgO / Molar mass of MgO
Number of moles of MgO = 4.0 g / 40.31 g/mol

Step 3: Determine the stoichiometric ratio.
Now, we need to determine the moles ratio between Mg, O₂, and MgO to balance the equation.

Based on the balanced equation:
2 mol of Mg + x mol of O₂ → 2 mol of MgO

By comparing the stoichiometric ratio, we can determine x:
2 mol of Mg / x mol of O₂ = 2 mol of MgO / 2 mol of Mg

Simplifying, we get:
1 mol of Mg / x mol of O₂ = 1 mol of MgO / 1 mol of Mg

This means the stoichiometric ratio is 1:1 between Mg and MgO, and we need x = 1 mole of O₂.

Step 4: Write the balanced equation.
Now that we know the stoichiometric ratio, we can write the balanced equation:
2 Mg + O₂ → 2 MgO

So, the balanced equation for the reaction is:
2 Mg + O₂ → 2 MgO

2Mg + O2 -> 2MgO

now convert to moles for amounts needed