Given f(x)=7-2x find f (x+5)
I'm not sure how to approach this problem.
I have done this so far:
F(x+5) = 7-2x
F(x+5)=7-2(x+5)
F(x+5)=7-(2x+10)
Not sure if this is right and what to do next.
I've been trying to solve it for a ay already and decided to ask on here. May I please get help on how to do this? It'll be great and I'll appreciate if you could help.
F(x) = 7 - 2x.
F(x+5) = 7-2(x+5).
F(x+5) = 7 - 2x - 10,
F(x+5) = -3 - 2x.
After you multiply the terms inside the parenthesis by (-2), you move the parenthesis.
To find f(x+5), substitute (x+5) into the function f(x)=7-2x. Here's the step-by-step process:
1. Start with the original function f(x)=7-2x.
2. Replace every occurrence of x in the function with (x+5).
f(x+5) = 7 - 2(x+5)
3. Distribute the -2 to both terms inside the parentheses:
f(x+5) = 7 - 2x - 2(5)
4. Simplify the expression inside the parentheses:
f(x+5) = 7 - 2x - 10
5. Combine like terms:
f(x+5) = -2x - 3
So the function f(x+5) is equal to -2x - 3.