Given: AB ∥ CD , BC ∥ AD , BD ∩ AC = O, M∈BC ; N∈AD Prove: BM = ND BD and AC are diagonals MN goes through the center which is also where BD and AC bisect and point O Can U Guys Put the Answer it would be a BIG HELP, Thanks (:

it is easy to show that ∆NOD ≅ ∆MOB check out vertical angles and recall that the diagonals bisect each other.

Gurp

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