AB ∥ CD , BC ∥ AD , BD ∩ AC = O, M∈BC ; N∈AD
Prove: BM = ND
BD and AC are diagonals
MN goes through the center which is also where BD and AC bisect and point O
Can U Guys Put the Answer it would be a BIG HELP, Thanks (:
it is easy to show that
∆NOD ≅ ∆MOB
check out vertical angles and recall that the diagonals bisect each other.