calculate the mass at 15.0 L at NH3 at 27 digree Celsius and 900 mm hg?
NH3?
PV=nRT
n=PV/RT
mass/molmassNH3= PV/RT
solve for mass. change temps to Kelvins, and use R in the units of mmHg*Liters/Kelvin
Mass of NH3 is 22.32
To calculate the mass of NH3 at 15.0 L, 27 degrees Celsius, and 900 mmHg, we will need to use the Ideal Gas Law equation:
PV = nRT
Where:
P = pressure (900 mmHg)
V = volume (15.0 L)
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature in Kelvin (27 degrees Celsius + 273.15 = 300.15 K)
First, let's rearrange the equation to solve for the number of moles (n):
n = PV / RT
Now, we can calculate the number of moles:
n = (900 mmHg) * (15.0 L) / (0.0821 L·atm/mol·K) * (300.15 K)
n = 553.43 mmHg·L / (0.0821 L·atm/mol·K) * (300.15 K)
n ≈ 20.36 mol
Finally, to find the mass, we need to multiply the number of moles by the molar mass of NH3 (ammonia):
Molar mass of NH3 = 14.01 g/mol (N) + (3 * 1.01 g/mol) (H)
Molar mass of NH3 ≈ 17.04 g/mol
Mass = n * Molar mass of NH3
Mass ≈ 20.36 mol * 17.04 g/mol
Mass ≈ 347.27 g
Therefore, the mass of NH3 at 15.0 L, 27 degrees Celsius, and 900 mmHg is approximately 347.27 grams.
To calculate the mass of NH3 at a given conditions, we need to use the ideal gas law equation which is:
PV = nRT
Where:
P = pressure of the gas (in this case, 900 mm Hg)
V = volume of the gas (15.0 L)
n = number of moles of the gas
R = ideal gas constant (0.0821 L·atm/K·mol)
T = temperature of the gas in Kelvin (27°C = 300K)
To find the number of moles, we rearrange the equation as follows:
n = PV / RT
n = (900 mm Hg * 15.0 L) / (0.0821 L·atm/K·mol * 300K)
Now, convert the pressure from mm Hg to atm:
1 atm = 760 mm Hg
n = (900 mm Hg * 15.0 L) / (0.0821 L·atm/K·mol * 300K * 760 mm Hg/atm)
Simplifying further:
n = (900 * 15.0) / (0.0821 * 300 * 760)
n ≈ 0.0373 moles of NH3
To calculate the mass, we need to use the molar mass of NH3 which is 17.03 g/mol.
Mass = moles * molar mass
Mass = 0.0373 moles * 17.03 g/mol
Mass ≈ 0.633 g
So, at the given conditions, the mass of NH3 is approximately 0.633 grams.