Two Small sphere are given positive electrical change. When they are 40cm apart the repulsion force between them has magnitude 0.25N what the charge on each sphere if two changes are equal

To find the charge on each sphere, we need to make use of Coulomb's Law, which states that the force of repulsion or attraction between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Here's how we can use Coulomb's Law to find the charge on each sphere:

1. Identify the given information:
- Distance between the spheres (r) = 40 cm = 0.4 m
- Magnitude of the repulsive force (F) = 0.25 N
- The charges on both spheres are equal (let's call this q)

2. Recall Coulomb's Law formula:
F = k * (q1 * q2) / r^2

Where:
- F is the magnitude of the force between the spheres
- k is the electrostatic constant (k = 9 x 10^9 Nm^2/C^2)
- q1 and q2 are the charges on the spheres
- r is the distance between the spheres

3. Rearrange the equation to solve for charge (q):
q * q / r^2 = F / k
q^2 = (F / k) * r^2
q = √((F / k) * r^2)

4. Plug in the values and calculate:
q = √((0.25 N / (9 x 10^9 Nm^2/C^2)) * (0.4 m)^2)

q ≈ 8.163 x 10^(-7) C

Therefore, the charge on each sphere is approximately 8.163 x 10^(-7) C.

if the "apart" is from center to center distance,

.25=kqq/.4^2
solve for q
Coulomb's law