[HCl]=0.1213M
Avg Amount HCl added: 14.15mL
Volume of Saturated Solution of Ca(OH)2 in NaOH used: 25 mL and its concentration was 0.05349 M.
1.)Calculate the total [OH ] in the saturated solution of Ca(OH)2 in sodium hydroxide
-> for this do I only find the mols of HCl? and thats it?? since ratio would be 1:1
2.)Calculate the [OH ] that comes from the dissolution of Ca(OH)2. The total [OH ] (calculated - -
above) is the sum of the [OH ] from the NaOH and the [OH ] from Ca(OH)2.
I dont get it. It appears that something is missing here. I don't know the solubility of Ca(OH)2 in NaOH. Without that I don't see how the amount of HCl can be apportioned between NaOH and Ca(OH)2 (or perhaps more information about the HCl titration).
I know how to work the problem but I'm confused by the data. What volume of saturated Ca(OH)2 solution did you use? Was that 25.00 mL? What was "it". The 0.05349 M was the concentration of what? Was that the NaOH concn or the Ca(OH)2. It might help if you restated the problem so that the sentences were complete. Also, I suggest you post as a new question at the top of the page.
Also, I suggest you post the Ksp you are using for Ca(OH)2.
To calculate the answers to these questions, you need to follow a series of steps:
1.) Calculate the total [OH-] in the saturated solution of Ca(OH)2 in sodium hydroxide:
Since HCl and NaOH undergo a neutralization reaction in a 1:1 ratio, the moles of HCl can be used to determine the moles of OH- in the solution. Here's how you get the answer:
Step 1: Calculate the moles of HCl added:
Moles of HCl = [HCl] x volume of HCl added (L),
Moles of HCl = 0.1213 M x 0.01415 L,
Step 2: Since the neutralization reaction between HCl and NaOH has a 1:1 ratio,
Moles of OH- = Moles of HCl.
So the total [OH-] in the saturated solution of Ca(OH)2 in sodium hydroxide is equal to the moles of HCl that were added.
2.) Calculate the [OH-] that comes from the dissolution of Ca(OH)2:
To calculate this, we'll use the information given about the volume and concentration of the saturated solution of Ca(OH)2 in NaOH.
Step 1: Calculate the moles of Ca(OH)2:
Moles of Ca(OH)2 = [Ca(OH)2] x volume of solution (L),
Moles of Ca(OH)2 = 0.05349 M x 0.025 L,
Step 2: Since Ca(OH)2 dissolves to give two moles of OH- for every mole of Ca(OH)2,
Moles of OH- from Ca(OH)2 = 2 x Moles of Ca(OH)2.
So the [OH-] that comes from the dissolution of Ca(OH)2 is equal to twice the moles of Ca(OH)2.
By calculating these two separate values, you can determine the total [OH-] in the saturated solution of Ca(OH)2 in sodium hydroxide, and the [OH-] that comes from the dissolution of Ca(OH)2.