To The Nearest Degree,find The Angle Of Elevation Of The Sun When A 9 Meters Vertical Casts A Shadow 3 Meters Long.
To The Nearest Degree,find The Angle Of Elevation Of The Sun When A 9 Meters Vertical Casts A Shadow 3 Meters Long.
Find the height of a tree if the angles of elevation is its top changes from 25 degree to 50degree as observer advanced 15 meter to ward its base.
72degree
Please give me answer
answer
To find the angle of elevation of the Sun, we can use the concept of similar triangles.
Let's label the height of the vertical object (the flagpole) as "h" and the length of its shadow as "s". In this case, we have h = 9 meters and s = 3 meters.
The angle of elevation of the Sun can be found by taking the inverse tangent of the ratio of the height (h) to the length of the shadow (s).
So, to find the angle of elevation, we can use the following formula:
angle of elevation = arctan(h / s)
Plugging in the given values, we have:
angle of elevation = arctan(9 / 3)
Now, let's evaluate this expression using a calculator or by looking up the arctan function table.
arctan(9 / 3) ≈ 1.2490439 radians
To convert this angle from radians to degrees, we need to multiply it by 180/π (approximately 57.2958 degrees).
angle of elevation ≈ 1.2490439 * (180/π) ≈ 1.2490439 * 57.2958 ≈ 71.565 degrees
Therefore, to the nearest degree, the angle of elevation of the Sun when a 9-meter vertical casts a shadow 3 meters long is approximately 72 degrees.