when hcl reacts with mg, how many grams of magnesium are needed to produce 100 grams of hydrogen?
balance the chemical reaction
Mg + 2HCl>>>H2 + MgCl2
so you need the same number of moles of Mg as you get in H2.
molesH2=100/2=50 moles
molesMg=same
gramsMg=atomicmassMg*50=24.3*50 grams.
Mg(s) +2HCl(aq)> MgCl2(aq) +H2(g)
RMM of H2 =2×1=2
No of mole of H2 =100/2
=50 moles
Mole ratio of Mg to H2 is 1:1
therefore, the no of moles of Mg is 50 moles
Mass= No of moles×RAM
=50×24
=1200g
To determine how many grams of magnesium are needed to produce 100 grams of hydrogen when reacting with hydrochloric acid (HCl), we need to calculate the stoichiometric ratio between magnesium and hydrogen.
The balanced chemical equation for the reaction of magnesium with hydrochloric acid is:
Mg + 2HCl -> MgCl2 + H2
From the equation, we can see that 1 mole of magnesium (Mg) produces 1 mole of hydrogen (H2).
Now, let's calculate the molar masses of the substances involved:
- Molar mass of Mg = 24.31 g/mol
- Molar mass of H2 = 2.02 g/mol
Using the molar masses, we can calculate the number of moles of hydrogen in 100 grams of H2:
Number of moles of H2 = mass of H2 / molar mass of H2
= 100 g / 2.02 g/mol
≈ 49.5 moles
Since 1 mole of magnesium produces 1 mole of hydrogen, we would need the same number of moles of magnesium to produce 100 grams of hydrogen.
Number of moles of Mg = 49.5 moles
Finally, we can calculate the mass of magnesium needed:
Mass of Mg = number of moles of Mg × molar mass of Mg
= 49.5 moles × 24.31 g/mol
≈ 1207.5 grams
Therefore, approximately 1207.5 grams of magnesium are needed to produce 100 grams of hydrogen in the given reaction.
To determine the number of grams of magnesium needed to produce 100 grams of hydrogen when it reacts with hydrochloric acid (HCl), we need to use stoichiometry, which is the calculation of the quantities involved in a chemical reaction.
First, we need to write and balance the chemical equation for the reaction between hydrochloric acid and magnesium (Mg):
2 HCl + Mg → MgCl2 + H2
From the balanced equation, we can see that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.
To find the amount of magnesium required, we need to convert the given mass of hydrogen gas into moles and then use the mole ratio to determine the moles of magnesium:
Step 1: Convert grams of hydrogen to moles
The molar mass of hydrogen is 2 g/mol (approximately). Thus, 100 grams of hydrogen is equal to:
100 g H2 * (1 mol H2 / 2 g H2) = 50 mol H2
Step 2: Use the mole ratio to find moles of magnesium
From the balanced equation, we know that for every 1 mole of hydrogen produced, we need 1 mole of magnesium.
Therefore, the moles of magnesium required is also 50 moles.
Step 3: Convert moles of magnesium to grams
The molar mass of magnesium is 24.3 g/mol (approximately). Thus, the mass of magnesium required is:
50 mol Mg * (24.3 g Mg / 1 mol Mg) = 1215 g Mg
Therefore, 1215 grams of magnesium are needed to produce 100 grams of hydrogen when it reacts with hydrochloric acid.