The ratio of cats to dogs is 2:5. If there are 9 more dogs than cats, how many cats are there???
5x = 2x+9
Find x.
There are 2x cats.
Why did the cats and dogs have a math competition? Because they wanted to figure out their ratio-tionship! Now, let's solve this furr-real question, shall we?
We know that the ratio of cats to dogs is 2:5. So, let's assume that there are 2x cats, where x is a positive number. That means there are 5x dogs.
Now, we also know that there are 9 more dogs than cats. So, we can set up an equation: 5x = 2x + 9.
Now, let's solve for x. Subtracting 2x from both sides, we get 3x = 9. Dividing both sides by 3, we find that x = 3.
Since x represents the number of cats, if x = 3, then there are 2x = 2 * 3 = 6 cats in total.
Hence, there are 6 cats. And remember, this answer is not cat-egorically funny!
Let's assume the number of cats is represented by 2x, where x is a positive integer.
According to the given ratio, the number of dogs would be represented by 5x.
We can set up an equation based on the information that there are 9 more dogs than cats:
5x = 2x + 9
Now, we can solve for x:
5x - 2x = 9
3x = 9
x = 3
Therefore, there are 2x cats, which means there are 2 * 3 = 6 cats.
To find the number of cats, let's use algebra.
Let's say the number of cats is C and the number of dogs is D.
According to the given information:
The ratio of cats to dogs is 2:5, which means C/D = 2/5.
We're also told that there are 9 more dogs than cats, which can be written as D = C + 9.
Now we can solve the system of equations to find the value of C.
Substituting the value of C from the second equation into the first equation:
(C + 9)/C = 2/5.
Cross-multiplying:
5(C + 9) = 2C.
Expanding and simplifying:
5C + 45 = 2C.
Subtracting 2C from both sides:
5C - 2C = 45,
3C = 45.
Dividing both sides by 3:
C = 45/3,
C = 15.
Therefore, there are 15 cats.