How do I factor this question?
3n^2-n-4=
You know the factors will be
(3n-?)(n+?)
or
(3n+?)(n-?)
where the ?? pairs are 1,4 or 2,2
So, just poke around a bit and you will soon find that
(3n-4)(n+1)
works
3n^2-n-4=
(3n-?)(n+?)
or
(3n+?)(n-?)
where the ?? pairs are 1,4 or 2,2
So, just poke around a bit and you will soon find that
(3n-4)(n+1)
works