The original Ferris wheel introduced at the 1893 World's Fair in Chicago had a diameter of 250 feet. What is the closest distance a person who rode this wheel travelled in one complete revoulution

Circumference probably equals about 785 or 760 Ft

It should be 750 - 790 feet

1,962.5 ft is the answer

C = pi * d

C = 3.14 * 250

C = ?

To find the closest distance a person who rode the original Ferris wheel travelled in one complete revolution, we can use the formula for the circumference of a circle.

The circumference of a circle is calculated using the formula: C = π * d, where C is the circumference and d is the diameter.

In this case, the diameter of the Ferris wheel is given as 250 feet. So, we can find the circumference:

C = π * 250 = 785.4 feet (rounded to one decimal place)

Therefore, when a person rides the original Ferris wheel and completes one full revolution, they would have traveled a distance of approximately 785.4 feet (rounded to one decimal place).