use formula from 2c to find the values of t and t
7 20
c)36,31,25,21,...
I don't understand it . could you work this one for me .
(a) do not know the formula
(b) your text formatting sucks. try writing fractions as 3/4 and sequence terms as t7 or t20
thank you Steve
To find the values of "t" and "t" for the given sequence 36, 31, 25, 21, ... using the formula 2c, we need to understand the pattern in the given sequence.
Looking at the sequence, we can see that each term can be obtained by subtracting a certain value from the previous term. Let's calculate the differences between consecutive terms:
31 - 36 = -5,
25 - 31 = -6,
21 - 25 = -4, ...
By examining the differences, we can observe that they are alternating between -5 and -6. This suggests that the sequence is decreasing by 5 and 6 alternatively.
Now, let's find the common difference between the consecutive terms. The common difference can be calculated by subtracting the second term from the first term:
31 - 36 = -5.
So, we see that the common difference is -5.
Now, using the formula 2c, we can find the next terms in the sequence. We can multiply the common difference (-5) by 2 to get the next term:
-5 * 2 = -10.
To obtain the next term, we subtract the calculated value from the previous term:
21 - 10 = 11.
Therefore, the next term in the sequence after 21 is 11.
To sum up, the values of "t" and "t" for the given sequence 36, 31, 25, 21, ... using the formula 2c are:
t1 = 36,
t2 = 31,
t3 = 25,
t4 = 21,
t5 = 11.