1.2 mol HCl and 3.9 mol NaOH react to this equation,
HCl + NaOH=NaCl + H20
If the limited reactant id HCl, calculate the amount of NaCl formed in moles.

Please help and explain how to solve this so I may understand it better please and thank you.

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  1. I = initial; i.e., start
    C = change
    E = equilibrium; end

    .......HCl + NaOH ==> NaCl + H2O

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