a point mass of 12.5 kg is hung from an 18.3 m long rope and swings back and forth with an amplitude of 2.34m. what is the oscillation period for the pendulum system?
To find the oscillation period of the pendulum system, we can use the equation:
T = 2π√(L/g)
where T is the period, L is the length of the rope, and g is the acceleration due to gravity.
In this case, L = 18.3m and g = 9.8 m/s^2 (approximate value for Earth's gravity).
Let's substitute these values into the equation:
T = 2π√(18.3 / 9.8)
Now, let's calculate it:
T = 2π√1.8673469387755101
T ≈ 2π * 1.365 (rounded to three decimal places)
T ≈ 8.561 seconds
Therefore, the oscillation period for the given pendulum system is approximately 8.561 seconds.