The volume equivalent of CO2(at stp)in the reaction NaHCO3+HCL=NaCL+H2O+CO2 is

To determine the volume equivalent of CO2 in the given reaction, we need to first balance the equation:

NaHCO3 + HCl -> NaCl + H2O + CO2

The balanced equation shows that for every one mole of NaHCO3 reacted, one mole of CO2 is produced.

Now, let's consider the volume of CO2 at STP (Standard Temperature and Pressure):

STP conditions are defined as a temperature of 273.15 Kelvin (0 degrees Celsius) and a pressure of 1 atmosphere (atm). At STP, one mole of any gas occupies 22.4 liters.

Since the balanced equation tells us that one mole of NaHCO3 produces one mole of CO2, we can conclude that one mole of CO2 occupies 22.4 liters at STP.

Therefore, the volume equivalent of CO2 (at STP) in the given reaction is 22.4 liters.

To determine the volume equivalent of CO2 at STP in the reaction NaHCO3 + HCL = NaCL + H2O + CO2, we need to use the stoichiometry of the reaction.

The balanced chemical equation for the reaction is:

NaHCO3 + HCl → NaCl + H2O + CO2

From the balanced equation, we can see that for every 1 mole of NaHCO3, 1 mole of CO2 is produced.

At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters.

Therefore, the volume equivalent of CO2 at STP is 22.4 liters.

Same as in your 2:27pm post