In a group of 25 boys, 20 play ice hockey and 17 play baseball. they all play at least one of the games.

What is the probability that a boy chosen at random from the class plays ice hockey but not baseball?
Note:is 3 the right answer

Thanks

To find the probability that a randomly chosen boy plays ice hockey but not baseball, we first need to determine the number of boys who play only ice hockey.

Given that there are 25 boys in total, we are told that 20 play ice hockey and 17 play baseball. However, some of these boys might play both sports. To find the number of boys who play only ice hockey, we need to subtract the number of boys who play both sports from the total number of boys who play ice hockey.

Let's calculate the number of boys who play both sports:
Number of boys playing both ice hockey and baseball = Total boys playing ice hockey + Total boys playing baseball - Total boys playing both sports
Number of boys playing both ice hockey and baseball = 20 + 17 - 25 (since the total number of boys is 25)
Number of boys playing both ice hockey and baseball = 20 + 17 - 25
Number of boys playing both ice hockey and baseball = 12

Now, to find the number of boys who play only ice hockey, we subtract the number of boys who play both sports from the total number of boys playing ice hockey:
Number of boys playing only ice hockey = Total boys playing ice hockey - Number of boys playing both ice hockey and baseball
Number of boys playing only ice hockey = 20 - 12
Number of boys playing only ice hockey = 8

So, there are 8 boys who play ice hockey only.

Now, to find the probability that a randomly chosen boy plays ice hockey but not baseball, we divide the number of boys playing ice hockey only by the total number of boys:
Probability = Number of boys playing ice hockey only / Total number of boys
Probability = 8 / 25

The probability is therefore 8/25, which is not equal to 3.

out of 25 boys, how many play one sport?

naanga naach

The answer is 8/25