In an arcade game, a 0.12 kg disk is shot across a frictionless horizontal surface by being compressed against a spring and then released. If the spring has a spring constant of 230 N/m and is compressed from its equilibrium position by 8.0 cm, what is the magnitude of the spring force on the disk at the moment it is released?
rub is still here
f=kx=230N/m * .08m
To find the magnitude of the spring force on the disk at the moment it is released, we can use Hooke's Law.
Hooke's Law states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position.
The formula to calculate the force exerted by the spring is:
F = -k * x
where:
F is the force exerted by the spring,
k is the spring constant, and
x is the displacement from the equilibrium position.
Given:
m = 0.12 kg (mass of the disk)
k = 230 N/m (spring constant)
x = 8.0 cm = 0.08 m (displacement)
Substituting the values in the formula, we can calculate the spring force:
F = - (230 N/m) * (0.08 m)
F = -18.4 N (rounded to one decimal place)
Therefore, the magnitude of the spring force on the disk at the moment it is released is 18.4 N.
To find the magnitude of the spring force on the disk at the moment it is released, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position.
Hooke's Law formula is given by:
F = -kx
where:
F is the spring force,
k is the spring constant, and
x is the displacement from equilibrium position.
In this case, the spring constant (k) is 230 N/m, and the displacement (x) is 8.0 cm, which is equivalent to 0.08 m.
Now, let's substitute these values into the formula:
F = -kx
F = -(230 N/m)(0.08 m)
F = -18.4 N
The negative sign indicates that the spring force is in the opposite direction of the displacement. However, since we're asked for the magnitude, we can ignore the negative sign.
Therefore, the magnitude of the spring force on the disk at the moment it is released is 18.4 N.