Three fourth of the number of girls in a school is equal to half of the number of the boys.if the school has 1420 pupils.how many of them are boys.
B+g=1420 ' 3g/4=b/2
B=1420-g ' 3g/4=1420-g/2
B=1420-568 4×3g/4=4×1420-g/2
B=852 3g=2840-2g
3g+2g=2840
5g=2840
G=2840/5
G=568
b+g = 1420
3g/4 = b/2
. . .
mali
mali
Well, if we let the number of girls be G and the number of boys be B, we can set up an equation. According to the problem, 3/4 of the number of girls is equal to half of the number of boys:
(3/4)G = (1/2)B
But we also know that the total number of pupils in the school is 1420:
G + B = 1420
Now, let's solve these equations using a little math magic. First, let's get rid of those fractions. We can do that by multiplying both sides of the first equation by 4 and the second equation by 2:
4(3/4)G = 4(1/2)B
2(G) + 2(B) = 2(1420)
Simplifying, we get:
3G = 2B
2G + 2B = 2840
Now, let's use the first equation to rewrite G in terms of B:
G = (2/3)B
Substituting this expression for G into the second equation, we get:
2((2/3)B) + 2B = 2840
Simplifying, we find:
(4/3)B + 2B = 2840
(10/3)B = 2840
Dividing both sides by (10/3), we find:
B = (2840 x 3) / 10
B ≈ 852.
So, if my calculations are correct (which they usually are, *wink*), there are approximately 852 boys in the school.
To solve this problem, we can set up a system of equations:
Let's assume the number of girls in the school is represented by 'g' and the number of boys is represented by 'b'.
According to the problem, three-fourths of the number of girls is equal to half of the number of boys, which we can write as an equation:
(3/4) * g = (1/2) * b
We also know that the total number of pupils in the school is 1420, so we can set up another equation:
g + b = 1420
Now we have a system of two equations:
(3/4) * g = (1/2) * b
g + b = 1420
To solve this system, we can choose one of the equations and express one variable in terms of another, and substitute it in the other equation.
Let's solve the second equation for 'g':
g = 1420 - b
Substituting this value of g in the first equation:
(3/4) * (1420 - b) = (1/2) * b
Now we can simplify and solve for 'b':
3 * (1420 - b) = 2 * b
4260 - 3b = 2b
5b = 4260
b = 4260 / 5
b = 852
Therefore, there are 852 boys in the school.
Total pupils = 1420
Let boys be x
so girls are 1420-x
ATQ
¾(1420-x) =½(x)
1065-¾(x)=½(x)
1065=(2x+3x)4
1065=5x/4
1065×4÷5
=852 boys