Can the equasion y=2x^2-3x+7 be solved in terms of y. How?
rewrite it as
2x^2-3x+7-y = 0
and in terms of the quadratic equation formula
a = 2
b = -3 and
c = 7-y
so x = (3 ± √(9 - 8(7-y))/4
= (3 ± √(8y-47))/8
there!
2x^2-3x+7-y = 0
and in terms of the quadratic equation formula
a = 2
b = -3 and
c = 7-y
so x = (3 ± √(9 - 8(7-y))/4
= (3 ± √(8y-47))/8
there!