In a titration experiment what would be the result on the concentration of the analyte if the drop counter did not count all the drops?

would it be lower since you would just be calculating the concentration at the same point on the curve just with a lower volume of titrant?

M = mols/L so the L would be smaller if you counted fewer drops. That means the M will be ......?

Larger. I dont know what i was thinking. i really overlooked that one. thank you

the drops happen, but are not counted

the fewer the drops to the endpoint, the lower the concentration of the unknown

the concentration would appear to be lower than it actually is

Yes, but I believe your reasoning is wrong. The drops actually happen in order to get to the equivalence point BUT you don't count them; therefore, the calculation point (say 10 drops instead of 12 drops) is LOWER which makes M = mols/L higher because the volume number you used in the calculation is lower. Note that your statement "the fewer the drops to the end point" is not what is happening. The drops to the end point stays the same BUT you use a smaller number in the calculation. It is the calculation that screws it up; not the titration itself.

Yes, you are correct. If the drop counter did not count all the drops in a titration experiment, the result would be a lower concentration of the analyte. This is because the concentration is determined by the volume of titrant required to reach a certain endpoint, which indicates complete reaction between the analyte and titrant.

In a titration experiment, a known volume of titrant (solution of known concentration) is slowly added to the analyte (solution of unknown concentration) until the reaction reaches its endpoint. The endpoint is usually determined by a visual change, such as a color change or the appearance of a precipitate.

By accurately counting all the drops, you can determine the volume of titrant required to reach the endpoint. If the drop counter fails to count some drops, it means that the volume of titrant added is underestimated. As a result, the calculated concentration of the analyte will be lower than the actual concentration. This is because you would be calculating the concentration at the same point on the curve but with a lower volume of titrant.

To ensure accurate results in a titration experiment, it is important to have precise and reliable methods for counting the drops of titrant. This can be done by using well-calibrated drop counters or other alternative methods such as measuring the volume of titrant dispensed using a burette.