A cooking pot contains 0.8kg of water at 100degree celcius what is the specific heat

Q=MxCxchange in temp=0.8x4.2x100=336KJ.

To find the specific heat of water, we need to use the formula:

Q = mcΔT

Where:
Q is the heat absorbed or released by the substance (in joules),
m is the mass of the substance (in kilograms),
c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius),
ΔT is the change in temperature (in degrees Celsius).

In this case, the water is initially at 100 degrees Celsius, so ΔT would be the difference between the final temperature and 100 degrees Celsius. However, the final temperature is not given in the question. Hence, it is not possible to calculate the specific heat with the given information.

To find the specific heat of water, you need to know the final temperature after heat is added or removed, or have additional information about the amount of heat absorbed or released by the substance.