what volume of oxygen is needed to react to complete reaction and to form 5cm of so3?
2SO2+O2=>2SO3 From the equ,1Cm3 of O2 formed 2Cm3 of 2SO3.Therefore, 5Cm3 will be formed by 5 X 1/2=2.5Cm3 of SO3.
Of O2
5Cm3 Of SO3 will be formed by 2.5Cm3 O2.
To determine the volume of oxygen needed to completely react and form 5 cm³ of SO₃, we need to use the balanced chemical equation for the reaction. In this case, the equation is:
2 SO₂ + O₂ → 2 SO₃
The equation tells us that for every 2 moles of SO₂, we need 1 mole of O₂ to produce 2 moles of SO₃.
To calculate the volume of oxygen, we need to follow these steps:
Step 1: Convert the volume of SO₃ to moles.
To do this, we need to know the density of SO₃ to convert from volume to moles. Let's assume that the density of SO₃ is 2.926 g/cm³.
Mass of SO₃ = Volume × Density
Mass of SO₃ = 5 cm³ × 2.926 g/cm³ = 14.63 g
Molar mass of SO₃ = 32.06 g/mol (sulfur) + 3 * 16.00 g/mol (oxygen) = 80.06 g/mol
Number of moles of SO₃ = Mass / Molar mass
Number of moles of SO₃ = 14.63 g / 80.06 g/mol = 0.1828 mol
Step 2: Use the mole ratio from the balanced equation to determine the moles of O₂ required.
From the balanced equation, we know that 2 moles of SO₂ react with 1 mole of O₂ to produce 2 moles of SO₃.
Moles of O₂ required = (Number of moles of SO₃) / 2
Moles of O₂ required = 0.1828 mol / 2 = 0.0914 mol
Step 3: Convert moles of O₂ to volume at the given conditions.
To convert moles of O₂ to volume, we need to know the molar volume of a gas at the given conditions. Assuming standard temperature and pressure (STP), the molar volume is 22.4 L/mol.
Volume of O₂ = Moles of O₂ × Molar volume
Volume of O₂ = 0.0914 mol × 22.4 L/mol = 2.05 L
Therefore, the volume of oxygen needed to completely react and form 5 cm³ of SO₃ is approximately 2.05 liters.