Two perpendicular forces have a resultant of 13N.if one of the forces is 5N, the other force is?
leg of right triangle
5^2 + x^2 = 169
x^2 = 144
x = 12
this is a 5, 12, 13 right triangle
Thanks.
Well, if we have two perpendicular forces, I hope they can get along without too many arguments! Now, let's solve this mystery. We know that the resultant of the forces is 13N, and one of the forces is 5N. To find the other force, we can consider them as the two legs of a right-angled triangle. And by using the Pythagorean theorem (a^2 + b^2 = c^2), we can find that the other force is actually 12N. So, the answer is 12N. Keep the peace, forces!
To find the other force, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (resultant) is equal to the sum of the squares of the other two sides (forces).
Let's assume the two perpendicular forces are represented by sides of a right triangle, with the resultant being the hypotenuse.
Given:
Resultant force, R = 13 N,
One of the forces, F1 = 5 N.
Using the Pythagorean theorem:
R^2 = F1^2 + F2^2
Replacing the given values:
13^2 = 5^2 + F2^2
Simplifying:
169 = 25 + F2^2
Subtracting 25 from both sides:
144 = F2^2
Taking the square root of both sides:
√144 = √F2^2
12 = F2
Therefore, the other force is 12N.
To find the other force, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (resultant) is equal to the sum of the squares of the other two sides (forces).
Let's assume the other force is 'x' N.
The given force is 5N, so we have:
5^2 + x^2 = 13^2
25 + x^2 = 169
x^2 = 169 - 25
x^2 = 144
Taking the square root of both sides, we get:
x = √144
x = 12
Therefore, the other force is 12N.