How would you graph this, i keep entering it only and keep getting it wrong. x and y axis are numbered 1 to 10. please help
y+5=-2/3(x-4)
This is a straight line, so all you need is two points.
Join them and you got your line.
pick x's that result in nice values of y
e.g. let x = 0,
y+5 = 0
y -5 ----> point (0,-5)
let x = 7
y+5 = -2/3(3) = -2
point (7,-2)
go for it
Awesome I got it! thank you
Actually I made an error.
I meant to say pick x = 4, which would result in 0 on the right side, so the point is (4,-5)
ok i corrected it, thanks again
To graph the equation y + 5 = -2/3(x - 4), you can follow these steps:
Step 1: Rewrite the equation in slope-intercept form (y = mx + b), where m represents the slope, and b represents the y-intercept.
y + 5 = -2/3(x - 4)
y = -2/3(x - 4) - 5
y = -2/3x + 8/3 - 5
y = -2/3x - 7/3
Step 2: Find the y-intercept:
The y-intercept is the value of y when x = 0. Substitute x = 0 into the equation and solve for y:
y = -2/3(0) - 7/3
y = -7/3
Step 3: Determine the slope:
The coefficient of x in the equation (-2/3x) represents the slope.
The slope is negative 2/3.
Step 4: Use the slope to find additional points:
Start from the y-intercept (-7/3) and use the slope to find additional points.
Move the numerator of the slope (-2) downward by 2 units and the denominator (3) to the side by 3 units. Repeat this process to find more points.
Step 5: Plot the points:
Plot the y-intercept (-7/3) and the additional points you found on the graph using the x and y axes numbered from 1 to 10.
Step 6: Connect the points:
Connect the points with a straight line to graph the equation y + 5 = -2/3(x - 4).
Remember to label the axes and any significant points on the graph for clarity.