sector 2 on a spinner is a 90 digrese (sorry for spelling) sector. if the spinner is spun twice, what is the probability that it will stop in sector 2 both times?

90º is a quarter of a circle

1/4 * 1/4 = ?

To find the probability of the spinner stopping in sector 2 both times, we need to know the total number of sectors on the spinner. Let's assume that there are 8 equal and numbered sectors on the spinner.

Since sector 2 is a 90-degree sector, it covers 90 degrees out of the total 360 degrees of the circle (360 degrees divided by 8 sectors equals 45 degrees per sector). Therefore, P(stopping in sector 2) = 90 degrees / 360 degrees = 1/4.

To calculate the probability of two independent events occurring together (in this case, spinning sector 2 on the spinner twice), you multiply the individual probabilities. So, the probability of spinning sector 2 twice in a row would be (1/4) * (1/4) = 1/16.

So, the probability that the spinner will stop in sector 2 both times is 1/16.