I'm a dad trying to help my daughter. Question is kx+6y-5=0 3x+2y+4=0. Need to find 1. Value of k such that the lines are perpendicular and 2. The angle of inclination of the second line given
perpendicular lines have slopes whose product is -1. So, you need
-k/6 * -3/2 = -1
k = -4
The 2nd line has slope -3/2. So, its angle of inclination is
arctan(-3/2) = -56.3°