Algebra2

What is an equation of a parabola with the given vertex and focus?

vertex(-2,5)

focus(-2,6)

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  1. I forgot my answer:

    (x+2)^2 = 4(y-5)

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  2. If you make a sketch, you will see that the directrix must be y = 4

    let P(x,y) be any point
    √( (y-6)^2 + (x+2)^2 ) = √((y-4)^2 + 0)
    square and expand
    y^2 - 12y + 36 + (x+2)^2 = y^2 - 8y + 16
    (x+2)^2 = 4y - 20
    (x+2)^2 = 4(y- 5)

    I agree

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  3. Thank you

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