# math

find the sets of valuse of x for which 4x^2 + 19x - 5 <= 0

1. 👍 0
2. 👎 0
3. 👁 120
1. 4x^2+19x-5 = (4x-1)(x+5)

The roots (places where the graph crosses the x-axis) are -5 and 1/4

So, where do you think the value is negative?

1. 👍 0
2. 👎 0

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