A 10 N object rests on a 10° incline. What is the normal force? What is the parallel force? A 10

kg object rests on a 10° incline. What are the normal and the parallel forces?

parallel force=mg*sin10

normal force=mg*cos10

To find the normal force and the parallel force on an object resting on an incline, we use basic trigonometry and the principles of Newton's laws of motion.

1. Normal force:
The normal force (N) is the force exerted by a surface perpendicular to that surface. In this case, it is the force exerted by the incline on the object perpendicular to the incline.

To find the normal force, we can use the equation:
N = mg cos(θ)
where m is the mass of the object and g is the acceleration due to gravity (approximately 9.8 m/s^2), and θ is the angle of the incline.

Given that the object has a weight of 10 N (weight = mass x acceleration due to gravity), we can substitute the values into the equation:
N = (10 N) cos(10°)

2. Parallel force:
The parallel force (P) is the force acting parallel to the incline. It is the force that opposes the downward force component due to gravity (mg sin(θ)).

To find the parallel force, we can use the equation:
P = mg sin(θ)

Given that the object has a weight of 10 N, we can substitute the values into the equation:
P = (10 N) sin(10°)

So, for the first scenario where the weight of the object is 10 N and the object rests on a 10° incline:
- The normal force (N) would be approximately N = (10 N) cos(10°)
- The parallel force (P) would be approximately P = (10 N) sin(10°)

For the second scenario where the mass of the object is 10 kg and the object rests on a 10° incline:
- The normal force (N) would be approximately N = (10 kg)(9.8 m/s^2) cos(10°)
- The parallel force (P) would be approximately P = (10 kg)(9.8 m/s^2) sin(10°)

Remember to convert the angles to radians if your calculator is set to use radians.