A ray of light travelling in air strikes the water surface at an angle of 30 degree calculate the angle of refraction if refractive index of glass is 1.5

Let me understand: where is the glass, under the water?

To calculate the angle of refraction, we can use Snell's law, which states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indices of the two media.

The refractive index of air is approximately 1, and the refractive index of glass is given as 1.5.

Let's label the angle of incidence as "i" and the angle of refraction as "r". We know that i = 30 degrees and the refractive index of glass = 1.5.

Using Snell's law, we have the equation:

sin(i) / sin(r) = refractive index of air / refractive index of glass

Substituting the given values, we get:

sin(30) / sin(r) = 1 / 1.5

To find the angle of refraction, we can rearrange the equation:

sin(r) = (sin(30) * refractive index of glass) / refractive index of air

sin(r) = (sin(30) * 1.5) / 1

Now, we can solve for the angle of refraction by taking the inverse sine of both sides:

r = arcsin((sin(30) * 1.5) / 1)

Calculating the value, we find:

r ≈ 48.59 degrees

Therefore, the angle of refraction is approximately 48.59 degrees.