Can someone help me write this as a function.
(6, -1); m= -5/3
Can you help?
If I was taught functions back in the Dark Ages, I don't remember them.
let's get the equation of that straight line:
y+1 = (-5/3)(x-6)
3y + 3 = -5x + 30
3y = -5x + 27
y = (-5/3)x + 9
f(x) = (-5/3)x + 9
Certainly! To write this as a function, we can use the point-slope form of a linear equation. The point-slope form is given by:
y - y₁ = m(x - x₁)
Where (x₁, y₁) is a point on the line and m is the slope.
Given the point (6, -1) and the slope m = -5/3, we can substitute these values into the point-slope form to get the function:
y - (-1) = (-5/3)(x - 6)
Simplifying this equation gives:
y + 1 = (-5/3)(x - 6)
Now, we can rearrange this equation to isolate y:
y + 1 = (-5/3)x + (5/3)(6)
y + 1 = (-5/3)x + 10
Subtracting 1 from both sides:
y = (-5/3)x + 10 - 1
y = (-5/3)x + 9
Therefore, the function is:
f(x) = (-5/3)x + 9