Find work done when 25kg weight lifted to a vertical height of 2m from the ground carrying to the same place by pushing it up and inclined plane make the angle of 30 degree (g=9.8)
Work = F * d = Mg * d = 25*9.8 * 2 = 490 J.
sin30 = 2/L. L = 4 m. = Length of incline.
Fp = Mg*sin30 = 25*9.8*sin30 = 122.5 N. = Force in parallel with
the incline.
Work = Fp*L = 122.5 * 4 = 490 J.
Explain second point
Why we multiply w.d with length of the incline
explain 2 part of the answer
Explane your answer
Why you multiplied by 4 when displacement is 2 m
Why u multiply by 4 ðŸ˜
To find the work done when lifting the weight vertically and pushing it up an inclined plane, we can use the formula
Work done = Force x Distance
Let's calculate the work done in each scenario:
1. Lifting the weight vertically:
To lift the weight vertically, we need to overcome the force of gravity pulling it down. The force of gravity can be calculated using the formula:
Force = mass x acceleration due to gravity
Given:
Mass (m) = 25 kg
Acceleration due to gravity (g) = 9.8 m/s^2
Force = 25 kg x 9.8 m/s^2 = 245 N
The distance lifted vertically (d) = 2 m
Work done = Force x Distance
Work done = 245 N x 2 m = 490 Joules
Therefore, the work done when lifting the weight vertically is 490 Joules.
2. Pushing the weight up an inclined plane:
To calculate the work done when pushing the weight up an inclined plane, we need to consider the component of force acting parallel to the inclined plane (Force_parallel). This force can be calculated using the formula:
Force_parallel = Force x cos(angle)
Given:
Force = weight (mg), where m = mass of the weight
Mass (m) = 25 kg
Acceleration due to gravity (g) = 9.8 m/s^2
Force = m x g = 25 kg x 9.8 m/s^2 = 245 N
Angle of the inclined plane (θ) = 30 degrees
Force_parallel = 245 N x cos(30 degrees) = 245 N x 0.866 = 212.87 N (rounded to two decimal places)
The distance moved along the inclined plane (d) = vertical height (h) = 2 m
Work done = Force_parallel x Distance
Work done = 212.87 N x 2 m = 425.74 Joules (rounded to two decimal places)
Therefore, the work done when pushing the weight up the inclined plane is approximately 425.74 Joules.
In conclusion, the work done when lifting the weight vertically is 490 Joules, and the work done when pushing it up an inclined plane (at a 30-degree angle) is approximately 425.74 Joules.