Physic

A 10 kg box starts from rest and is then pulled horizontally 27 meters across the ground by a rope. The rope has a force of 100N applied to it and forms an angle of 50 degree to the ground. The coefficient of kinetic friction is 0.50 for this surface.


(a)How much work is done by the applied force?
(b)How much work is done by friction?
(c) How much work is done by gravity?
(d)How much work is done by the normal force?
(e)What;s the total work done on the box?
(f)what is the change in potential energy of the box?
(i)What is the change in potential energy of the box?
(j)how long did it take for the box to travel 18 meters?
(k) what is the total power?

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  3. 9
asked by Katy needs help
  1. a) work=100cosTheta*distance
    b)frictionwork=mu(mg-100sinTheta)*distance

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    2. 0
    posted by bobpursley

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