Results for 'The parallel sides of trapezium are 32 cm and 20 cm its non paraller sides are equal each being 10 cm find the are of trapizum
Draw the diagram, with two congruent triangles at the ends.
Notice that the two right triangles are 6-8-10.
To find the area of a trapezium, you can use the following formula:
Area = ((a + b) / 2) * h
Where:
a and b are the lengths of the parallel sides
h is the height (the distance between the parallel sides)
In this case, we have:
a = 32 cm
b = 20 cm
h = 10 cm
Substituting these values into the formula, we have:
Area = ((32 + 20) / 2) * 10
= (52 / 2) * 10
= 26 * 10
= 260 cm²
Therefore, the area of the trapezium is 260 cm².
To find the area of a trapezium, you can use the formula:
Area = (a + b) * h / 2
where:
a and b are the lengths of the parallel sides
h is the perpendicular distance between the parallel sides
In this case, the parallel sides of the trapezium measure 32 cm and 20 cm respectively. The non-parallel sides are equal and each measures 10 cm. To find the height of the trapezium, we can use the Pythagorean theorem.
Let's label the trapezium as ABCD, with AB and CD being the parallel sides of lengths 32 cm and 20 cm respectively. Since the non-parallel sides are equal and measure 10 cm, we can say that AD = BC = 10 cm.
To find the height, we need to consider that AD and BC are perpendicular to AB and CD respectively. Hence, we have two right triangles (e.g. triangle ADE and triangle BCF) formed by the trapezium.
Using the Pythagorean theorem, we can find the height (h) by calculating the distance between the bases AB and CD.
First, let's find the length of DE:
DE^2 = AD^2 - AE^2
DE^2 = 10^2 - (AB - CD)^2
DE^2 = 10^2 - (32 - 20)^2
DE^2 = 10^2 - 12^2
DE^2 = 100 - 144
DE^2 = -44
As you can see, the value under the square root is negative. This implies that the height is imaginary and the trapezium does not exist in this case. Please review the given dimensions of the trapezium and ensure they are correct.