A 25-mL sample of 0.160M solution of NaOH is titrated with 17 mL of an unknown solution of H2SO4 What is the morality of the sulfuric acid solution.
don't know if sulfuric is moral or not
... however, it is diprotic (two H+)
?M = .16 * 25/17 * 1/2
To determine the molarity of the sulfuric acid (H2SO4) solution, we can use the concept of stoichiometry and the balanced chemical equation. The balanced chemical equation for the reaction between NaOH and H2SO4 is as follows:
2 NaOH + H2SO4 → Na2SO4 + 2 H2O
From the balanced equation, we can see that the ratio of NaOH to H2SO4 is 2:1. This means that for each mole of H2SO4, two moles of NaOH are needed.
First, let's determine the number of moles of NaOH in the 25 mL of the 0.160M NaOH solution:
Molarity (M) = moles/Liter
moles NaOH = Molarity × Volume (L)
moles NaOH = 0.160 M × 0.025 L
moles NaOH = 0.004 mol
Since the ratio of NaOH to H2SO4 is 2:1, the number of moles of H2SO4 used in the reaction is also 0.004 mol.
The volume of the unknown H2SO4 solution used in the titration is 17 mL. To find the molarity of the H2SO4 solution, we can rearrange the equation:
Molarity = moles H2SO4 / Volume (L)
Molarity = 0.004 mol / 0.017 L
Molarity ≈ 0.235 M
Therefore, the molarity of the sulfuric acid solution is approximately 0.235 M.