physics 11

a water bomber flying with a horizontal speed of 85m/s at a height of 3000 m drops a load on a fire below. how far in front of the target fire should the load be released?

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  1. how long does it take to fall 3000m?
    h=1/2 a t^2...
    t=sqrt(2*3000/9.8)

    distance in front=85m/s*timeabove

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  2. it's asking for meters. the answer is 2103m just don't know how to get there.

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  3. Lord, I just told you how:
    distanceinfront=85*sqrt(2*3000/9.8)

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  4. h=1/2 at^2
    t^2=(2*3000)/9.8
    t^2=612.244898
    t=24.74358297sec
    d=vt
    d=85m/s*24.74358297s
    d=2103meters

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