Two vertices of a right triangle have the coordinates (−2, 5) and (9, 5) .
What is the length of the side formed by these vertices?
Let A (-2,5) be (x1,y1) and B(9,5) be (x2,y2).
Using distance formula,
distance^2(d^2)=(x2-x1)^2+(y2-y1)^2
= [9-(-2)]^2 + [5-5]^2
= 11^2 + 0^2
= 11^2
= 121
Now, converting the above information to its square root to obtain the actual length.
distance (d)= /121
= 11 units.
same y-coordinates
a vertical line
length is the difference of the x-coordinates
oh it 11
To find the length of a side formed by two vertices, we can use the distance formula. The distance between two points (x1, y1) and (x2, y2) in a Cartesian plane is given by the formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the two vertices are (-2, 5) and (9, 5). Let's label the coordinates accordingly:
(x1, y1) = (-2, 5)
(x2, y2) = (9, 5)
Now we can substitute these values into the distance formula:
Distance = √((9 - (-2))^2 + (5 - 5)^2)
Simplifying this equation, we get:
Distance = √((9 + 2)^2 + 0^2)
Distance = √(11^2)
Distance = √121
Distance = 11
Therefore, the length of the side formed by the given vertices is 11 units.