# chemistry

3.05 g hydrated copper sulfate produces 1.94 g of anhydrous salt.Assuming complete removal of all water of crystallisation,determine tha formula of hydrated copper sulfate.

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1. 3.05 g - 1.94 = 1.11 g H2O abd 1.94 g CuSO4

mols H2O = grams H2O/molar mass H2O
mols CuSO4 = grams CuSO4/molar mass CuSO4.

Now fine the ratio of the two to each other. The easy way to do that is to divide the smaller number by itself (thereby making sure it is 1.00). Then divide the other number by the same small number. Round to whole numbers and that will be the formula of the hydrated salt. You should get CuSO4.5H2O

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2. Thank you so much for this wonderful help which is very helpful. I appreciate this and looking foward to be part of this group.

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