What is the volume of a 5.2 molarity solution made with 115g of LiF?
I've only learned in class how to go from volume to molarity. How do you do this one?
molarity=mass*1/molmass*1/volumeLiters
volumeliters=Mass/Molarity*molmass)
= 115g/(5.2*molmass)
molmassLiF=25.9g
volumeliters=115/(5.2*25.9) liters
To find the volume of a solution, given its molarity and mass of solute, you can use the formula:
Volume (in liters) = Mass of Solute / (Molarity x Molar Mass of Solute)
In this case, you have a solution with a molarity of 5.2 M and 115g of LiF as the solute.
First, you need to determine the molar mass of LiF. Li has a molar mass of approximately 6.94 g/mol, and F has a molar mass of approximately 18.998 g/mol. So the molar mass of LiF is 6.94 + 18.998 = 25.938 g/mol.
Next, plug the values into the formula:
Volume = 115g / (5.2 M x 25.938 g/mol)
Now, multiply the molarity (5.2 M) by the molar mass of LiF (25.938 g/mol) to find the denominator:
Volume = 115g / (134.7776 g/L)
Finally, divide the mass of the solute (115g) by the denominator (134.7776 g/L) to get the volume:
Volume = 0.8538 L
Therefore, the volume of the 5.2 M solution made with 115g of LiF is approximately 0.8538 liters.