9x-4y=-3
8x-3y=-1
72x-32y=24
-72x+27y=9
-5y=-15
y=3
8x-3y=-1
8x-3(3)=-1
8x - 9=-1
8x =8
I just need to know if it is correct
9 x - 4 y = - 3 Multiply both sides by 8
72 x - 32 y = - 24
8 x - 3 y = - 1 Multiply both sides by 9
72 x - 27 y = - 9
72 x - 32 y = - 24
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72 x - 27 y = - 9
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- 32 y - ( - 27 y ) = - 24 - ( - 9 )
- 32 y + 27 y = - 24 + 9
- 5 y = - 15 Divide both sides by - 5
y = 3
9 x - 4 y = - 3
9 x - 4 * 3 = - 3
9 x - 12 = - 3
9 x = - 3 + 12
9 x = 9 Divide both sides by 9
x = 1
are you doing elimination
so, you got x=1
Use that in the other equations and see whether you get the same value of y for each.
If so, then that x and y are the solution.
To solve the system of equations:
Equation 1: 9x - 4y = -3
Equation 2: 8x - 3y = -1
One method to solve this system is by using the method of elimination. The goal is to eliminate one variable by multiplying one or both of the equations by appropriate numbers so that the coefficients of one of the variables will add up to zero when the equations are added or subtracted.
Let's eliminate the x variable by multiplying Equation 2 by 9 and Equation 1 by 8:
Equation 1 (multiplied by 8): 72x - 32y = -24
Equation 2 (multiplied by 9): 72x - 27y = -9
Now, subtract Equation 2 from Equation 1 (to eliminate x):
(72x - 32y) - (72x - 27y) = -24 - (-9)
Simplifying:
72x - 32y - 72x + 27y = -24 + 9
-32y + 27y = -15
-5y = -15
Divide both sides by -5:
y = 3
Now substitute the value of y back into either of the original equations to find x. Let's use Equation 1:
9x - 4y = -3
9x - 4(3) = -3
9x - 12 = -3
9x = 9
Divide both sides by 9:
x = 1
Therefore, the solution to the system of equations is x = 1 and y = 3.